Question

in triangle ABC , DE||BC. AB = 15, cm, BD = 6cm, AC = 25 cm, then AE is equal to​

Answer 1

✬ AE = 15 cm ✬

Step-by-step explanation:

Given:

• In ∆ABC , DE is parallel to BC.
• AB = 15 cm , BD = 6 cm , AC = 25 cm

To Find:

• What is the meaure of AE ?

Solution: Since, DE || BC so by Thales'Theorem,

• AD/DB = AE/EC

➬ AD = (AB – BD)

➬ AD = (15 – 6) = 9 cm

Let AE be x cm so EC will be (25 –x) cm.

Now, Putting values on theorem

$\implies{\rm }$ AD/DB = AE/EC

$\implies{\rm }$ 9/6 = x/25 – x

$\implies{\rm }$ 9(25 – x) = 6x

$\implies{\rm }$ 225 – 9x = 6x

$\implies{\rm }$ 225 = 6x + 9x

$\implies{\rm }$ 225 = 15x

$\implies{\rm }$ 15 = x = AE

Hence, meaure of AE is x = 15 cm.a

Answer 2

Answer:

15 cm

Step-by-step explanation:

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