In triangle ABC, DE// BC , AD = 3 cm,DB = 4 cm,DE = 2 cm and BC = x cm then x equals to
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Given : In triangle ABC, DE// BC , AD = 3 cm,DB = 4 cm,DE = 2 cm and BC = x
To Find : Value of x
Solution:
Comparing ΔADE & ΔABC
∠A =∠A ( common Angles)
∠ADE = ∠ABC ( corresponding angles DE║BC )
∠AED = ∠ACB ( corresponding angles DE║BC )
ΔADE ≈ ΔABC (AAA )
=> AD/AB = DE/BC
AD = 3
DB = 4
AB = AD + DB = 3 + 4 = 7
DE = 2
BC = x
=> 3/7 = 2/x
=> x = 14/3
x = 14/3
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