Question

In triangle ABC, DE//BC,AD=4.8cm,AE=6.4cm,EC=9.6cm, find the AB

Answer 1

Answer:

(A) The length of BC 40°(B) AB : BC : CA = 15 : 20 : 16

Step-by-step explanation:

Given as :

For any Triangle ABC

The ratio are as

AB : BC = 3 : 4

BC : AC = 5 : 4

Or, \dfrac{AB}{BC} = \dfrac{3}{4} × \dfrac{5}{5}

So, \dfrac{AB}{BC} = \dfrac{15}{20}

And \dfrac{BC}{AC} = \dfrac{5}{4} × \dfrac{4}{4}

So , \dfrac{BC}{AC} = \dfrac{20}{16}

Therefor the ratio can be written as

AB : BC : CA = 15 : 20 : 16

Let The length of AB = 15 x

The length of BC = 20 x

The length of CA = 16 x

A/Q

AB = 30°

Or, 15 x = 30°

∴ x = \dfrac{30}{15}

i.e x = 2°

Put the value of x in BC value

i.e The length of BC = 20 × 2° = 40°

Hence, (A) The length of BC 40°

And (B) AB : BC : CA = 15 : 20 : 16 answer

Step-by-step explanation:

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