In triangle ABC, DE||BC.FIND X
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AD = x , AB = 2x+1 , AE = x+3 , AC = 2x+8
By, Basic proportionality theorem
AD /AB = AE/AC
x/2x+1. = x+3/ 2x+8
cross multiplication to get
2x^2 + 8x = 2x^2 + 7x + 3
bring everything to left side
2x^2 -2x^2 + 8x -7x -3 =0
x - 3 =0
:. x=3
HOPE IT IS HELPFUL
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