In triangle ABC,DE II BC. Find AC
ab is 5 cm and ad is 3 cm and bd is 2cm and ae is 4.5 cm
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Given: AD = 2cm, DB =3cm, AB = 5cm
and DE || BC
Basic Proportionality theorem which states that. if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio. So, by basic proportionality theorem.
DB
AD
=
EC
AE
3
2
=
EC
5
EC=
2
5×3
EC=7.5cm
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