Math, asked by Abhirajaram, 1 year ago

In triangle ABC, DE is parallel to base BC, with D on AB and AB and E on AC .if AD/DB = 2/3, find BC/DE

Answers

Answered by Hiteshbehera74
124
∆ADE ~ ∆ABC. (AAA TEST)

THEREFORE, AB/AD = BC/DE

AD/DB = 2/3
DB/AD = 3/2
DB + AD/AD = 3 +2/2
AB/AD = 5/2

AB/AD = BC/DE
HENCE, BC/DE = 5/2
Answered by prachiy791
12

It may help you...

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