In triangle ABC, DE is parallel to base BC, with D on AB and AB and E on AC .if AD/DB = 2/3, find BC/DE
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∆ADE ~ ∆ABC. (AAA TEST)
THEREFORE, AB/AD = BC/DE
AD/DB = 2/3
DB/AD = 3/2
DB + AD/AD = 3 +2/2
AB/AD = 5/2
AB/AD = BC/DE
HENCE, BC/DE = 5/2
THEREFORE, AB/AD = BC/DE
AD/DB = 2/3
DB/AD = 3/2
DB + AD/AD = 3 +2/2
AB/AD = 5/2
AB/AD = BC/DE
HENCE, BC/DE = 5/2
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