In triangle abc de is parallel to BC a d is equal to 5 cm BD is equal to 7 cm and ac is equal to 18 cm find a e andec
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Answer:
∴ x = 7.5 cm
Step-by-step explanation:
It is assumed that the point D lies on AB and the point E lies on AC.
Draw a figure with the given data.
Let AE = x cm
then EC = (18 - x ) cm
AD = 5 cm
BD = 7 cm
we have AE/EC = AD/BD (By basic proportionality theorem )
x / 18 - x = 5 / 7
∴ 7x = 5 (18-x)
∴ 7x = 90 - 5x
∴ 7x + 5x = 90
∴ 12x = 90
∴ x = 90/12
∴ x = 7.5 cm
Thus, the length of AE is 7.5 cm in triangle ABC.
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