Question

in triangle abc de is parallel to bc ad= 5cm db = 7 cm and Ac = 18 cm find the length of ae and ce ​

Answer 1

Answer:

∴AE=7.5 cm AND EC- 10.5 cm

Step-by-step explanation:

GIVEN : AD=5cm, DB=7cm, AC=18cm

(AE+EC)=18 .................[ Because A-E-C]

∴ AE = (18-CE)..................(1)

By BPT (Basic Proportionality Theorem),

$\frac{AD}{DB} =\frac{AE}{EC}$

$\frac{5}{7} =\frac{18-EC}{EC}$

From equation (1),

$5(EC)=7(18-EC)\\5EC=126-7EC\\12EC=126\\EC = \frac{126}{12}$ ∴EC=10.5 cm ...................(2)

∴AE=18- EC = 18-10.5 = 7.5 cm

∴AE=7.5 cm AND EC- 10.5 cm