Question

in triangle ABC DE is parallel to BC AD= xcm DB= x-2 AE=x+2 EC=x-1 find x

Answer 1

Answer:

X=4

Step-by-step explanation:

given BC is parallel to DE

SO by BPT theorem

AD/DB=AE/EC

X/X-2 =X+2/X+1

X(X-1)=(X+2)(X-2)

X^2-X=X^2-4

-X=-4

X=4

Answer 2

Given, DE//BC

$\frac{AD}{DB} = \frac{AE}{EC} \\ \\ \frac{x}{x -2 } = \frac{x + 2}{x - 1} \\ \\ x(x - 1) = (x + 2)(x - 2) \\ \\ {x}^{2} + x = {x}^{2} + 4 \\ \\ x = 4$