Question

in triangle ABC ,DE IS PARALLEL TO BC AND DE:BC=5:8 the find the ratio of trapezium DCEB to Triangle ABC​

Answer 1

Step-by-step explanation:

Draw AF perpendicular to BC.

AF=AG+GF=> GF+GF(AG=GF)

AF=2GF.

ar(trapezium DCEB)/ar(∆ABC)=½×(5+8)×(GF)/½×8×(AF).

=> 13×GF/8×(2GF)

=> 13/16.

Answer 2

Step-by-step explanation:

refer to two attachments

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