In triangle abc de is parallel to bc . Area of triangle ade is 32sq cms ad=4cms and ab =6 CMs find the area of triangle abc
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area of ABC =72 cm sq
firstly ∆ADE~∆ABC by AA then with th theorem ratio of area of ~ ∆ is = to ratio of sq of corresponding side
firstly ∆ADE~∆ABC by AA then with th theorem ratio of area of ~ ∆ is = to ratio of sq of corresponding side
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