Question

.In triangle ABC ,DE is parallel to BC.Find the value of x ,if AD=x+1,DB=x-1,AE=x+3,EC=X

Answer 1

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Your Question Is :

.In triangle ABC ,DE is parallel to BC.Find the value of x ,if AD=x+1,DB=x-1,AE=x+3,EC=X

Your Answer Is :

Method 1:

AD/DB=AE/CE (by BPT)

X/x+1=x+3/x+1

x(x+5)=(x+1)(x+3)

5x=4x+3

x=3

Method 2:

DE//BC

ie., AD/DB=AE/EC. {by BT}

X/X+1=X+3/X+5

X(X+5)=(X+1)(X+3)

X^+5X=X^+3X+X+3

5X-3X-X-3=0

X-3=0

X=3

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