Question

in triangle abc DE is parallel to BC prove that AD/BD=AE/EC​

Answer 1

Answer:

i hope it's help n plz mark in brilliant

Answer 2

Step-by-step explanation:

In triangle ABC BC II DE

then we get a new triangle i.e ADC

Now we have to prove these two triangle as congruent

In triangle ABC and ADC

we have

∠A=∠A (common)

∠D=∠B (corresponding ∠)

∠E=∠C

Therefore ΔABC and ΔADC are congruent

then AD/BD=AE/EC ( by CPCT)

Plz mark as brainiest