Question

In triangle ABC,DE is parallel to BC,so that AD=2.4cm,AE=3.2cm, and EC=4.8cm,Then AB=?

Answer 1

DE II BC
;BY BPT THEORUM
AD/DB = AE/EC
LET DB be X
:: 2.4/X = 3.2/4.8
::X =3.6
:. AB= AD + DB
=6
AB = 6cm