In triangle ABC DE is parallel to BC So that AD = 2.5 cm AE = 3.2 cm EC = 4.8 cm than AB = ___________
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given DE//BC in▲ABC
then by theorem
AD/DB=AE/EC
=> DB=AD×EC/AE
=2.5×4.8/3.2
=3.75
then AB=AD+DB
=2.5+3.75
=6.25
then by theorem
AD/DB=AE/EC
=> DB=AD×EC/AE
=2.5×4.8/3.2
=3.75
then AB=AD+DB
=2.5+3.75
=6.25
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