in triangle ABC,DE os drawn parallel to BC intersecting AB at D and E respectively. if AD=10cm,DB=15cm,and AE=2.4cm,find EC
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Given : in triangle ABC,
DE is drawn parallel to BC intersecting AB and AC at D and E respectively.
AD=10cm, DB=15cm,and AE=2.4cm,
To Find : EC
Solution:
DE is drawn parallel to BC
Using BPT / Thales theorem
AD/DB = AE/EC
=> 10/ 15 = 2.4/EC
=> 2/3 = 2.4/EC
=> EC = 3.6
Length of EC = 3.6 cm
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