In triangle ABC, DE parallel BC , AD = 2 cm , DB = 3 cm DE ratio BC is equal to
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Answer: The answer to the above given question is option b.
Step-by-step explanation:
Given that in triangle ABC ,
AD = 2 cm
DB = 3 cm and DE ║ BC
In the Δ ADE and Δ ABC
Angle A is common
∠ ADE ≈ ∠ ABC ( corresponding angles )
Here two angles of triangle are equal to another two angles of another triangle. This is called A A or AAA theorem.
Therefore by A. A similar condition
so AD ÷ AB = DE ÷ BC
2 ÷ 5 = DE ÷ BC
So the DE : BC is equal to 2 : 5
Here are two links provided to know something more intresting facts about what does a similar triangle mean and it's similarity rules.
https://brainly.in/question/21755428
https://brainly.in/question/13530059
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