In triangle ABC, DE parallel BC find x if AD=x, BD=x+1,AE=x+3,CE=x+5
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by BPT Thereom
AD/BD= AE/CE
X / X+1 = X+3 / X+5
CROSS MULTIPLY AND THE SOLVED
X^2 +5X = X^2 +4X+ 3
X=3
AD/BD= AE/CE
X / X+1 = X+3 / X+5
CROSS MULTIPLY AND THE SOLVED
X^2 +5X = X^2 +4X+ 3
X=3
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