Question

in triangle abc de parallel to ab if ad=2x,dc=x+3,be=2x-1 and ce=x.then find the value of x

Answer 1

It's by Thales theorem

Answer 2

AD = 2x ,DC = x + 3, BE =2x - 1 ,CE = x

Using Thales Theorem

$\bf\huge\frac{CD}{AD} = \frac{CE}{BE}$

$\bf\huge\frac{x+3}{2x} = \frac{x}{2x-1}$

5x = 3

$x=\bf\huge\frac{3}{5}$