Question

In triangle ABC , DE parallel to AB. If
CD=3cm , EC=4 cm , BE=6 cm .then
DA is equal to........​

Answer 1

Answer:

ur answer is 4.5cm

Step-by-step explanation:

by using B.P.T

Answer 2

DA is equal to 4.5 cm.

Given:

In ΔABC, DE || AB, CD = 3cm , EC = 4 cm , BE = 6 cm

The figure of the given data is in the attachment below.

To Find : The value of DA.

Concept used :

According to BASIC PROPORTIONALITY THEOREM (BPT) :

"If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio."

Solution :

Step 1 of 2: Using BASIC PROPORTIONALITY THEOREM (BPT) in ΔABC :

In ΔABC, DE || AB, we have

$\frac{CD}{DA} = \frac{EC}{BE}$

Step 2 of 2: Substitute the given values in step 1:

$\frac{3}{DA} = \frac{4}{6}$

$4DA = 6 \times 3$

$DA = \frac{18}{4}$

$DA = \frac{9}{2}$

DA = 4.5 cm

Hence, the value of DA is 4.5 cm.

Learn more on Brainly :

In the figure given below . If AD = 2.4 cm, DB = 3.6 cm, AC = 5 cm. Find AE.

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In a $\triangle ABC$, D and E are points on the sides AB and AC respectively such that $DE \parallel BC$

(i) If AD = 6 cm, DB = 9 cm and AE = 8 cm, find AC.

(ii) If $\frac{AD}{DB} = \frac{3}{4}$ and AC = 15 cm, find AE.

(iii) If $\frac{AD}{DB} = \frac{2}{3}$ and AC = 18 cm, find AE.

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