Question

In triangle ABC , DE parallel to BC,AD= 3cm,BD= 4cm ,DE= 2 cm, BC= ?

Answer 1

Answer:

14 / 3

Step-by-step explanation:

By Thales Theorem..

In ∆ ABC and ∆ ADE

$\frac{ad}{ab} = \frac{de}{bc} \\ \\ \frac{3}{3 + 4} = \frac{2}{bc} \\ \\ \frac{3}{7} = \frac{2}{bc} \\ \\ bc = \frac{7 \times 2}{3} \\ \\ = \frac{14}{3}$