Question

in triangle abc de parallel to bc and ad / db = 3 / 5 then ae / ec​

Answer 1

Step-by-step explanation:

By Proportionality theorem

1. ad/db=ae/ec
2. hence ae/ec=3/5

Answer 2

The value of $\frac{ae}{ec} = \frac{3}{5}$

Step-by-step explanation:

In Δ ABC

de is parallel to bc. So  Δ ABC  ≅ ΔADE

⇒ $\frac{ad}{db} = \frac{ae}{ec}$

⇒ $\frac{3}{5} = \frac{ae}{ec}$

⇒ $\frac{ae}{ec} = \frac{3}{5}$

Thus the value of $\frac{ae}{ec} = \frac{3}{5}$