Question

In Triangle ABC, DE parallel to BC , find the value of x. IF AD=x ,DB=x+1, AE=3cm& EC=5cm
A.1.5cm
B.1.8cm
C.2.5cm
D. 3.0cm​

Answer 1

Step-by-step explanation:

In Δ ABC, DE ∥ BC

∴DBAD=ECAE

(By basic proportionality theorem)

⇒x−2x=x−1x+2

⇒x(x−1)=(x+2)(x−2)

⇒x2−x=x2−4

⇒x=4.