Question

In triangle abc de parallel to BC if ad = 2 cm ab = 5 cm and a = 4 cm find AC

Answer 1

Step-by-step explanation:

Hence ad is 2cm and ab is 5 cm.

Then it's given ae is 4.

Hence, ac is 2.5 or 3

Answer 2

Answer:

$\boxed{\red{\sf Hence \ the \ value \ of \ AC \ is\ 10cm .}}$

Step-by-step explanation:

Correct Question : In a ∆ABC , DE || BC . If AD = 2cm , AB = 5cm and AE = 4cm . Find AC .

And we need to find out the the value of AC . Here we can make use of , Basic Proportionality Theorem or Thales Theorem .

• According to which , if a line is drawn parallel to one side of the triangle to cut the other two sides at two distinct points , then the other sides are divided in the same ratio .

$\red{\bigstar}\underline{\textsf{ According to \textbf{ Thales Theorem } :- }}$

$\sf\dashrightarrow \dfrac{ AD}{AB}=\dfrac{AE}{AC} \\\\\\\sf\dashrightarrow \dfrac{2cm}{5cm}=\dfrac{4cm}{AC} \\\\\\\sf\dashrightarrow AC =\dfrac{ 4cm \times 5cm}{2cm} \\\\\\\sf\dashrightarrow \boxed{\pink{\sf AC = 10cm }}$

Hence the value of AC is 10cm .

$\rule{200}7$

$\tiny\qquad\qquad\qquad\qquad\qquad\boxed{\red{\textsf {\textbf{Hence \ the \ value \ of \ AC \ is 10cm .}}}}$

$\rule{200}7$