Question

in triangle abc, DE parallel to BC prove ab/ ad = ac / ec ​

Answer 1

Step-by-step explanation:

Proof: From the figure , ABC and ADE we have

ABC = ADE .......( Corresponding angles are equal.)

ACB = AED.......( Corresponding angles are equal.)

Then by AA axiom of similarity we can conclude that ABC ADE

We know that corresponding sides of a similar triangles are proportional.

∴ AB / AD = AC / AE

⇒ ((AD + DB) / AD) = ((AE / EC) / AE) .... (∵ AB = AD + DB and AC = AE + EC)

⇒ 1 + (DB / AD) = 1 + (EC / AE)

⇒ (DB / AD) = EC / AE

⇒ (AD / DB) = AE / EC .....(by taking reciprocals)

Hence, AD / DB = AE / EC

Answer 2

Answer:

Please type the question again..

It is not clear..

Whether DE is mid point??