Question

In triangle ABC DE parallel to BC triangle ADE is 50 degree triangle ACB is 40 degree find triangle ABC and triangle BAC

Answer 1

Answer:

If angle ADE = 50°

then angle ABC = 50° (by alt. int. angle)

If angle BCA = 40°

then, angle. DEA = 40° (by alt. int. angle)

Now, in ∆ ADE

angle ADE + angle DEA + angle BAC = 180°

50° + 40° + angle BAC = 180°

90° + angle BAC = 180°

so, angle BAC = 90°