in triangle abc, e and f respectively are equal sides ab and ac of triangle abc . show that bf= ce
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In an Isosceles ∆ when two sides are equal (e = f) then the two base angles are always equal to each other
(Ang. B = Ang. C).
So when a straight line is drawn from one base angle to its opposite side of the ∆ ( Ang.B → Side f), the measure of the line draw from another base angle to its opposite side of the ∆ (Ang.C → Side e) is also equal to the measure of the previous line drawn.
.°. Hence proved Bf = Ce
(Ang. B = Ang. C).
So when a straight line is drawn from one base angle to its opposite side of the ∆ ( Ang.B → Side f), the measure of the line draw from another base angle to its opposite side of the ∆ (Ang.C → Side e) is also equal to the measure of the previous line drawn.
.°. Hence proved Bf = Ce
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