Math, asked by AbhinavNarayan, 1 year ago

In triangle ABC,E is midpoint of median AD and BC produced meets side AC at point Q .show that the BE:EQ =3:1

Answers

Answered by bhatiamona
75

Answer:

Step-by-step explanation:

Let's take point Y on seg AC such that DY | | BX.

As D is a midpoint of BC, by converse of midpoint theorem, XY=YC.

Applying midpoint theorem in triangle CDY, BX=2DY.

As E is a midpoint of AD & EX | | DY,  

AX=XY.

Applying midpoint theorem in triangle DAY, EX= DY/2

BE/EX = BX-EX / EX  

           = 2DY - DY/2 / DY/2

            = 3DY / 2 * 2/YD

              = 3DY/DY

               = 3:1.

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Answered by shikhapallaviyadav
35
Answer:this is the answer

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