Question

In triangle ABC, E is the mid point of the median AD, the extended BE intersects AC at

point F. If AC=10.5cm,then find the length of AF.​

Answer 1

Answer:

3.5cm

Step-by-step explanation:

So,

AF=1/3 of AC

AF=1/3×10.5

AF=3.5 cm

IF YOU FOUND IT HELPFUL THEN PLZ MARK AS BRAINLIEST

Answer 2

Step-by-step explanation:

given:

in triangle abc ,is the midpoint of the median ad and extended be intersect the side AC at the point E

required to find

the length of EF

construction

through the point d a line parallel to BF is drawn which intersect the side AC at the point

proof

in triangle BFV ,D is the midpoint of BC hence (ad is median)

DG is parallel to EF (according to the construction)

g is the midpoint of FC,

if FG is equal to GC ....(i)

in triangle abc ,e is the midpoint of side ad..(given)

F is the midpoint of AG

AF equal to FG equal to AC

so,AF =FG

AF =1\3AC

EF =1\3*10.5

EF =3.5 cm