In triangle abc e is the midpoint of ab and a straight line 3m and parallel to bc cut csat and if ac is equal to 6 cm then the length of a n is
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Step-by-step explanation:
IN ΔAMN ΔABC
Since MN∣∣BC
∠AMN=∠ABC (Corresponding angles)
∠ANM=∠ACB (Corresponding angles)
∴ΔAMN∼ΔABC(By $$AA similarity criterion)
⇒ABAM=ACAN=BCMN(CPST)
Since, M is mid-point of AB,
AM=21AB,or,ABAM=21or,ABAM=ACAN=21ACAN=215AN=21[∵AC=5cm]AN=25cm=2.5cm
Also, ABAM=BCMN=
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