Question

In triangle ABC, E is the midpoint of median AD such that BE is produced meets AC at F. If AC=10.5 cm, then AF=?

Answer 1

Answer:

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Answer 2

Answer:

3.5 cm

Step-by-step explanation:

In ∆ABC, E is the mid-point of median AD

Such that BE produced meets AC at F

AC = 10.5 cm

Draw DG || AF

In ∆ADG

E is mid-point of AD and EF || DG

∴ F is mid-point of AG

⇒ AF = FG …(i)

In ∆BCF

D is mid-point of BC and DG || BF

∴ G is mid-point of FC

∴ FG = GC …(i)

From (i) and (ii)

AF = FG = GC = 13 AC

But AC = 10.5 cm

∴ AF = 13 AC = 13 x 10.5 = 3.5 cm