in triangle abc express sigma r1 cot(a/2) in terms of s.
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We know that ,
(i) r1 = s × tan A/2,
(ii) r2 = s × tan B/2
(iii) r3 = s × tan C/2
Given: r1 cot A/2 + r2 cot B/2 + r3 cot C/2
= s × tan A/2 cot A/2 + s × tan B/2 cot B/2 + s × tan C/2 cot C/2
= s + s + s
= 3s
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