in triangle ABC exterior angle at b=150° and interior angle c=70° then find interior angle A
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Step-by-step explanation:
Theorem: An measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles.
So In our case ∠CAB and ∠CBA are the two non-adjacent interior angles corresponding to the exterior angle.∠DCA. and
∠ACB and ∠BAC are the two non-adjacent interior angles corresponding to the exterior angle.∠ABE.
Hence, ∠CAB+∠CBA=∠DCA..........(1)
And,
∠CAB+∠BCA=∠ABE..........(2)
Adding (1) and (2) we get,
∠ABE+∠DCA=180°+∠BAC
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