in triangle abc find Angle B A D figure is given that
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angle BAD =[180 -(angle B +angle C)]1/2
ans-30°
ans-30°
adirustom:
y u make a half of
angle b and angle c
no its the half of angle A
ohh sorry then y u did half of angle a on which basis
as angle A=angle(BAD +CAD)
and AC bisects angle A into two halves
i know this but bad is not equal to cad
ac is not a medain then how it is dividing it into two halves
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30 degree will be the answer
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corresponding side ke samne wala angle bhi apas me Equal hota he
okk thanks for help
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