in triangle abc find bc if angle a is 90 degree ac = 100√3cm and ab = 100 cm
Answers
Answered by
1
Answer:
Two equilateral triangles can be termed with the base AB.
But vertex D should be at maximum distance from C.
Therefore, triangle ABD will be preferred.
Now,ΔABD is equilateral triangle.
∴AB=BD=AD=10
3
cm
In right ΔABC
(BC)
2
=(AB)
2
+(AC)
2
(20)
2
=(10
3
)
2
+(AC)
2
(AC)
2
=400−300
AC=10
In ΔACD,∠CAD=90
0
+60
0
=150
0
cos∠CAD=
2(AD)(AC)
(AD)
2
+(AC)
2
−(CD)
2
[∵cosC=
2ab
a
2
+b
2
−c
2
]
cos
6
5π
=
2(10
3
)(10)
10
3
2
+10
2
−CD
2
−
2
3
=
200
3
300+100−(CD)
2
−300=400−(CD)
2
(CD)
2
=700
CD=10
7
cm
Answered by
5
AB^2==AC^2+BC^2
H^2=P^2+B^2
100^2=100√3^2+B^2
10000=30000+B^2
10000-30000=B^2
-20000=B^2
√-20000=B
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