In triangle ABC find the angles B, C if angle A is 40 degrees and also find the exterior which is marked 3x
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Step-by-step explanation:
a=40 degrees
let b be 'x'.
also exterior angle is 3x
then, 40+x=3x
2x=40
x=20
then angle b =x=20 degrees
A+B+C=180 DEGREES
40+20+C=180
60+C=180
C=180-60
C=120
So,3x=3*20=60 degrees
so angle b=20 degrees
angle c =120 degrees
exterior angle=60 degrees
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