In triangle abc find the measure of angles form by joining the
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Given : ABC is a triangle with ∠A = 40°, ∠B = 80°, ∠C = 60°.
Let D, E, F be the mid points of side BC, AC, AB respectively.
Now according to mid point theorem, The line segments joining the mid points of the sides of a triangle is parallel to the third side of triangle.
⇒ FE // BC
⇒ FE // BD and FE // DC ..... (1)
ED // AB
⇒ ED // AF and ED // FB ..... (2)
FD // AC
⇒ FD // AE and FD // EC ..... (3)
from (1), (2) and (3) we can conclude that
AFDE, BFED, DFEC are parallelogram.
Also opposite angles of a parallelogram are equal
⇒ ∠FAE = ∠FDE = 40°
⇒ ∠FBD = ∠FED = 80°
⇒ ∠DCE = ∠DFE = 60°
∴ In ΔDEF
∠D = 40°, ∠E = 80° and ∠F = 60°
⭐✌️✌️ HOPE YOU HELP !!
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