in triangle ABC 'H" is the orthocentre and "I" is the incentre. if angle BHC=angle BIC then the value of angle A is
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Step-by-step explanation:
In general, in any triangle
"Angle BOC is equal to angle 2*A.
Angle BHC is equal to angle 180-A.
Angle BIC is equal to 90+A/2."
Let me know if you want the proof of above ones.
Now,H and I lie on the same circle implies that angle BHC is equal to angle BIC. (Angles in same segment theorem:The angle subtended by an arc or a line in a circle in the same segment are equal)
Hence,
90+A/2=180-A
implies A=60 degrees.
Hence, angle BOC is equal to 2*60=120 degrees.
You need not assume that it is an equilateral triangle as the other writer suggested.
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