Question

In triangle ABC, height AD is 3cm and its area is 9cm then its base BC IS
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Answer 1

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Answer 2

Its base BC is 6 cm.

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Let's understand a few concepts:

We will use the following formula of the area of a triangle to solve the given problem:

$\boxed{\bold{Area \:of\:a\:triangle = \frac{1}{2} \times base \times height}}$

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Let's solve the given problem:

Here we have,

ABC is the triangle

BC is the base of the Δ ABC

The height of the Δ ABC i.e., AD = 3 cm

The area of the Δ ABC = 9 cm²

Therefore, by using the above formula, we can form an equation as,

$Area = \frac{1}{2} \times BC \times AD$

on substituting the value of Area = 9 cm² and AD = 3 cm

$\implies 9 = \frac{1}{2} \times BC \times 3$

$\implies BC = \frac{9 \times 2 }{3}$

$\implies BC = \frac{18 }{3}$

$\implies \bold{BC = 6\:cm}$

Thus, its base BC is 6 cm.

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