in triangle ABC if 3 angle A = 4 angle B = 6angleC calculate angle A angle B and angle C
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Let 3∠A= 4∠B=6∠C= X
∠ A= X/3, ∠B=X/4, ∠C=X/6
∠A+∠B+∠C=180° (ASP)
X/3+X/4+X/6=180°
(4x+3x+2x)/12 = 180°
9x= 180×12
x= 240°
∠A= x/3 = 240/3=80°
∠B= x/4=240/4=60°
∠C= x/6 = 240/6= 40°
∠ A= X/3, ∠B=X/4, ∠C=X/6
∠A+∠B+∠C=180° (ASP)
X/3+X/4+X/6=180°
(4x+3x+2x)/12 = 180°
9x= 180×12
x= 240°
∠A= x/3 = 240/3=80°
∠B= x/4=240/4=60°
∠C= x/6 = 240/6= 40°
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