In triangle ABC if 3angleA=4angleB=6angleC, calculate the angle
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Given, 3angle(A) = 4angle(B) = 6angle(C)
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Let us consider them as 3A=4B=6C
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We know, angle sum property of a triangle is always 180.
A + B + C =180
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Multiply both sides with 3
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3A + 3B + 3C = 180 X 3
4B + 3B + 3C = 540
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7B + 3C =540
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Multiply both sides with 2.
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14B + 6C = 1080
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14B + 4B = 1080
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18B = 1080
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B = 60
A=80
C=40
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