Question

In triangle ABC if A = 100, AD bisects A and AD is perpendicular to BC, then B=​

Answer 1

Answer:

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Step-by-step explanation:

Given that in △ABC, ∠A = 100° Also given that AD ⊥ BC Consider △ABD ∠BAD = 100/2 (AD bisects ∠A) ∠BAD = 50° ∠ADB = 90° (AD perpendicular to BC) We know that the sum of all three angles of a triangle is 180°. Thus, ∠ABD + ∠BAD + ∠ADB = 180° (Sum of angles of △ABD) Or, ∠ABD + 50° + 90° = 180° ∠ABD =180° – 140° ∠ABD = 40°

Answer 2

In △ABC,∠BAD+∠ADB+∠DBA=180°

by angle sum property of a triangle.

50°+90°+∠DBA=180°

⇒∠DBA=180°−140° =40°

∴∠B=40°