Question

in triangle ABC , if( a^2+b^2/a^2-b^2) sin(A-B)=1and the triangle is not right angled , then cos (A-B)​

Answer 1

Answer:

Given that, In ΔABC,∠C=900

A+B+C=1800

A+B=1800−900

A+B=900........(1)

Then,

a2−b2a2+b2sin(A−B)

Using sine rule, and we get,

sinAa=sinBb=sinCc=k

(ksinA)2−(ksinB)2(ksinA)2+(ksinB)2sin(A−B)

=sin2A−sin2Bsin2A+sin2Bsin(A−B)

=