In triangle ABC , if A = (3, 2), B = (1, 4) and the mid point of AC is (2, 5), then find the mid point of BC.
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Step-by-step explanation:
mid point of BC
before that coordinate of C
x 1 + x2 /2 = 2 by section formula
3 + x2 = 4
x2 = 1
y2 + y1 /2 = 5
2 + y2 = 10
y2 = 8
coordinate of C (1,8)
required mid point of BC
x2 + x1/2 = 1 + 1 /2 = 1
y2 + y1 /2 = 4 +8 /2 = 12/2 = 6
therefore required mid point is
(1,6)
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