in triangle ABC if a=(b-c)secx then prove that tanx=((2(bc)^1÷2)÷(b-c))×sin(A÷2)
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Answer:
sinθ=
a
a
2
−(b−c)x
k
2
secθ=
(b−c)
a
cosθ=
a
(b−c)
a
sinA
=
b
sinB
=
c
sinC
=
λ
1
sinB−sinC
sinA
=secθ
cos(
2
B+C
)sin(
2
B−C
)
sinA
=secθ
sin(
2
B−C
)
cos
2
A
=secθ
tan(a)
2
B−C
=(
b+c
b−c
).cot
2
A
Step-by-step explanation:
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