Question

In triangle ABC, if AB = 7cm, BC = 8cm and CA = 5cm, then find the area of triangle ABC. *​

Answer 1

√10×3×2×5

10√3 cm^2

. . . . . . . .

Answer 2

Answer:

Area = 10√3 cm²

Step-by-step explanation:

Sides = 7 cm, 5 cm and 8 cm

Perimeter = AB + BC + CA

P = 7 + 5 + 8,

P = 20 cm

Semi - perimeter = 20/2 = 10 cm

According to Heron's formula:

$Area = \sqrt{s(s-a)(s-b)(s-c)}$

$Area = \sqrt{10(10-7)(10-8)(10-5)}$

$Area = \sqrt{10*3*2*5}$

$Area = \sqrt{2*5*3*2*5}$

$Area = 10\sqrt{3} cm^{2}$