In triangle abc if ab=ac and ad is median then angle adc =to
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6
CONSIDER triangle ADB and triangle ADC
AD = AD ( common)
AB=AC (given)
BD = CD ( because AD is a median)
We can say triangle ADB and triangle ADC are congruent by SSS congruency
As angle ADB and angle ADC are equal by cpct
And we know BC is straight line
Angle ADB + Angle ADC = 180
both are 90
Hence ANGLE ADC IS 90 DEGREES
AD = AD ( common)
AB=AC (given)
BD = CD ( because AD is a median)
We can say triangle ADB and triangle ADC are congruent by SSS congruency
As angle ADB and angle ADC are equal by cpct
And we know BC is straight line
Angle ADB + Angle ADC = 180
both are 90
Hence ANGLE ADC IS 90 DEGREES
Answered by
1
Given : ∆ABC is an isosceles triangle such that AB = AC and
AD is median to BC.
To Find : ∠adc
Solution:
∆ BAD and ∆ CAD
AB = AC Given
AD = AD Common
BD = CD = BC/2 as AD is the median
Using side - side - side congruence property
∆ BAD ≅ ∆ CAD
=> ∠ADC ≅ ∠ADB
AB is straight line
Hence ∠ADC and ∠ADB form a linear pair
=> ∠ADC + ∠ADB = 180°
=> 2∠ADC = 180°
=>∠ADC = 90°
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