In triangle abc,if ab=ac and angle a=70,find angle b and anglec
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in an isosceles triangle abc,
if ab=ac,then angle C= angle B(angles opposite to equal sides are equal)
let angle C and angle B be'x'
then,
angle A + angle B + angle C = 180°[angle sum property of a triangle ]
=»70°+x+ x=180°
70°+2x=180°
2x=180°-70°
2x=110°
x=110÷2
x=55°
therefore, angle b=55° and angle c=55°
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