In triangle ABC if AB=AC and<A = 50° then find the measure of <B.
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Answer:
IN ∆ ABC
We know that,
angle A + B+ C = 180°
GIVEN,
AB=AC
A= 50°
SO,
ABC + BCA+ CAB = 180°. ( Equation - 1)
ABC + BCA + 50 = 180°. [ A = 50°]
ABC+ BCA + 50 = 180°
ABC + BCA = 180 - 5
ABC + BCA = 130°. [Equation - 2 ]
NOW,
Put value of equation 2 in equation 1
ABC + BCA + CAB = 180°
130 + 50 = 180°. [ As per eq 1 ]
180° = 180°
Hence , it proved that all sides of ∆ are equal
So,
A = B = C
A = 50°
B = 50°
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