In triangle ABC,if AB =BC then how angle A=angle B?
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Step-by-step explanation:
Draw AD perpendicular to BC
In triangle ABD and triangle ACD
AB=AC (given)
AD=AD(common in both triangles)
Angle ADB=Angle ADC(Each 90°,since AD perpendicular to BC)
Hence,∆ABD conguent to ∆ACD(R.H.S)
Therefore,Angle B=Angle C(c.p.c.t.c)
Hence proved.
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